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Paraphin [41]
3 years ago
8

Simplify the expression (3x^2+4x-3)-(2x-1)

Mathematics
2 answers:
Sliva [168]3 years ago
5 0
(3x^2 + 4x - 3) - (2x - 1) \\ \\ 3x^2 + 4x - 3 - 2x + 1 \\ \\ 3x^2 + 4x - 3 - 2x + 1 \\ \\ 3x^2 + (4x - 2x) - 3 + 1 \\ \\ 3x^2 + 2x - 3 + 1 \\ \\ 3x^2 + 2x - 2 \\ \\ Answer: 3x^2 + 2x - 2
Eva8 [605]3 years ago
4 0
(3x^2+4x-3)-(2x-1) = 3x^2 + 4x -3 -2x + 1\\\\ = 3x^2 + 4x -2x -3 + 1\\\\ = \boxed{3x^2 +2x -2}
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What is the solution to the equation? 4x - 8 = 16<br>need this at least by tomorrow!<br>thank you!​
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Answer:

x = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

4x - 8 = 16

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 8 to both sides:                    4x = 24
  2. Divide 4 on both sides:               x = 6

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                   4(6) - 8 = 16
  2. Multiply:                              24 - 8 = 16
  3. Subtract:                             16 = 16

Here we see that 16 does indeed equal 16.

∴ x = 6 is the solution to the equation.

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