The correct answer is: [D]: " 7.2 units" .
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Explanation:
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Use the Pythagorean theorem:
a² + b² = c² ;
in which: "6 units" and "4 units" equal the lengths of the right angle (formed by the rectangle); and "c" is the length of the diagonal of the rectangle, or the "hypotenuse", of the right triangle formed by the rectangle; We wish to solve for "c" ;
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6² + 4² = c² ; Solve for "c" ;
↔ c² = 6² + 4² ;
= (6*6) + (4*4) ;
= 36 + 16 ;
= 52 ;
c² = 52 ;
Take the "positive square root" of each side of the equation; to isolate "c" on one side of the equation; and to solve for "c" ;
√(c²) = √52 ;
c = √52 ;
At this point, we know the 7² = 49 ; 8² = 64 ; so, the answer is somewhere between "7" and "8" ; yet closer to "7" ; so among the answer choices given;
The correct answer is: [D]: " 7.2 units" .
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However, let use a calculator:
c = √52 = 7.2111025509279786 ; which rounds to "7.2" ;
which corresponds to:
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Answer choice: [C]: " 7.2 units" .
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Answer:
49N
Step-by-step explanation:
Step one
Given
When the force of 63 N acts on a certain object
the acceleration of the object is 9/ms^2
Firstly, we need to calculate the mass m
F=ma-------1
m= F/a
m= 63/9
m= 7kg
Step two:
Also, if the acceleration of the object becomes 7 m/s^2
then the force
Note: the mass remains the same= 7kg
F=ma
F=7*7
F= 49N
You have the following data set: 10, 14, 12, 16, 13, 15, 20, 16, 10, 14. Based on the values in the given data set, which of the
kolbaska11 [484]
Trequency distribution table:
10.....2
14.....2
12.....1
16.....2
13.....1
15.....1
20....1
Answer:
The number 11 is NOT INCLUDED in the frequency distribution
100×16.60=1,660
Sam cost
1,660+1,660×0.06=1,759.6