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qaws [65]
3 years ago
6

The class has 360 unit cubes in a bag.

Mathematics
2 answers:
Klio2033 [76]3 years ago
4 0
1.A  2.D  3.A. is the answers for them :)
n200080 [17]3 years ago
3 0
The answer for the first question is 45.  360 divided by 8 is 45.
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5x+10=5(x+2) what is the answer I’ll give u 85 points
asambeis [7]

Answer:

All real numbers of x.

Step-by-step explanation:

5x+10=5(x+2) have the exact same equations on both sides.

5x+10=5x+10

If both are graphed, they will intersect each other for every value of x.

5 0
3 years ago
Read 2 more answers
What is the solution to this inequality?<br> X-6&lt;-4
Gekata [30.6K]

Step-by-step explanation:

x - 6 <  - 4

x - 6 + 6 <  - 4 + 6

x < 2

8 0
2 years ago
I don’t know how to find the answer to number 10
Igoryamba

The student mixed the letters. If you swicth the order of the letters then the equation would be true. y=4x. So if you plug in all the numbers into the equation you get the correct value for why. For example 4×2=8, 4×4=16, and so on.

8 0
3 years ago
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For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
3 years ago
Find each difference.
serg [7]

Answer: -9s^2 + 4s-2

Step-by-step explanation:

(-6s^2 +12s-8)-(3s^2 + 8s-6)\\\\=-6s^2 + 12s-8-3s^2 - 8s+6\\\\=\boxed{-9s^2 +4s-2}

3 0
2 years ago
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