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Artemon [7]
3 years ago
15

9,573 times 8,797 divided by 10,789​

Mathematics
2 answers:
DanielleElmas [232]3 years ago
6 0

Answer:

(9573 x 8797) / 10789 = 7805.51

Step-by-step explanation:

I got the answer by multiplying 9,573 and 8,797.

9,573 x 8,797= 84,213,681

Then, dividing that product by 10,789

84,213,681/10,789= 7805.51

<h2>7805.51</h2>

mel-nik [20]3 years ago
3 0

Answer:

7805.51312

Step-by-step explanation:

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A new cellular phone tower services all phones within a 20 mile radius. Doreen lives 16 miles east and 12 miles south of the tow
Lunna [17]

Answer: Yes.

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the Pythagorean Theorem:

c^2 = a^2 + b^2

Where c is the hypotenuse of the triangle (in this case the distance between Doreen’s house and the tower) and a and b are the other sides.

Replacing with the values given:

c^2 = 16^2 + 12^2

c^2 = 256+144

c^2 = 400

c = √400

c = 20 miles

So, she is within the area serviced by the tower (20 miles)

Feel free to ask for more if needed or if you did not understand something.

3 0
4 years ago
The cost of tuition at a college is $13,500 and is increasing at a rate of 3.75% each year. Use an exponential function to find
poizon [28]

13=

500=

3.75%=0.0375

year=0.0375

4 years=0.0375

i think thats it

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3 years ago
Find |x| when x = 15 and x = – 15.
777dan777 [17]

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3(x + 1)² = 12<br> Solve for x.
vichka [17]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
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