Answer:30 drinks
Step-by-step explanation:
Answer:
$16 per pound
Step-by-step explanation:
We want to find the price per pound.
Therefore, we must divide the cost by the pounds.

We know it costs $144 for 9 pounds of pears. Therefore, $144 is the cost and there are 9 pounds.

Divide.

It costs $16 for each pound of pears.
Answer:
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Responder:
24 litros; 16 litros; 4 litros
Explicación paso a paso:
Dado que:
Gasolina consumida = 20 litros
Sea la cantidad de gasolina en el tanque = x
Primera parte del viaje = 2/3 de x
Segunda parte del viaje = 1/2 de (x - 2x / 3)
Cantidad de gasolina en el tanque:
2x / 3 + 1/2 (x - 2x / 3) = 20
Solución para x
2x / 3 + x / 2 - x / 3 = 20
(4x + 3x - 2x) / 6 = 20
5 veces / 6 = 20
5 veces = 20 * 6
5 veces = 120
x = 120/5
x = 24
Cantidad de gasolina en el tanque = 24 litros
Litros consumidos en cada etapa:
Primera parte = 2/3 de 24 = 48/3 = 16 litros
2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros
Answer:
a) The probability that this whole shipment will be accepted is 30%.
b) Many of the shipments with this rate of defective aspirin tablets will be rejected.
Step-by-step explanation:
We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.
We select a sample of size 48 and test for defectives.
If more than one aspirin is defective, the batch is rejected.
The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48
We have to calculate the probabilities that X is equal or less than 1: P(X≤1).
