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zysi [14]
2 years ago
6

Which of the following is true of the data represented by the box plot

Mathematics
1 answer:
zmey [24]2 years ago
4 0

Answer:

The data is skewed to the bottom and contains an outlier.  

Step-by-step explanation:

1. Test for outlier

An outlier is a point that is more than 1.5IQR below Q1 or above Q3.  

IQR = Q3 - Q1 = 74 - 51 = 23

1.5 IQR  = 1.5 × 23 = 34.5

51 - 15 = 36 > 1.5IQR

The point at 15 is an outlier.

2. Test for normal distribution

The median is not in the middle of the box.  

Rather, it cuts the box into two unequal parts, so the data does not have a normal distribution.

3. Test for skewness

The longer part is to the left of the median, so the data is skewed left.

 

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The booster club raised $102 in there car wash. They want to buy $18 soccer balls for the soccer team. Write and solve an inequa
sergey [27]

Answer:

X=5

Step-by-step explanation:

102=18x, then divide both sides by 18 which gives you 5.666667 but you cant buy half a ball they can only afford 5 balls with $12 left over.

3 0
3 years ago
The graph of the function f(x) is shown below.
faust18 [17]
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥

domain is how far the x values go
x is left to right

we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain



range
highest to lowest y value

range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]



Domain=[-3,5)
Range=[-1,3]


B. read above and understand it
5 0
3 years ago
Factor the expression completely over the complex numbers.<br><br> y^4+12y^2+36
Brums [2.3K]
Y⁴ + 12y² + 36
Now factorize the expression
y⁴ + 6y² + 6y² + 36
= y²(y² + 6) + 6(y² + 6)
= (y² + 6) (y² + 6)
<span>Now 6 is not the perfect square and according to rule, binomial can not be factored as the difference of two perfect squares.
</span>so multiply both.
(y² + 6)² is the answer.
7 0
3 years ago
Read 2 more answers
If a = 2 and b = -3, find the value of a3 - b2. <br> A.-31<br> B.-23<br> C.-1<br> D.15
valentinak56 [21]

Hello!

So let's first start out by solving the left side of the equation:

2 to the third power is 8

The right side now: -3 to the second power is -9

In total: 8- (-9)

So your answer is C) -1

I hope it helps!

3 0
3 years ago
Read 2 more answers
Can you explain how to do 13 please
Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
3 0
3 years ago
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