60 minutes is 20% of how many minutes show work on a number line

Write a trinomial which is degree 2, where the coefficient of the highest degree term is 7.

Nady [450]

Answer:

7x^2 - 2x - 3.

Step-by-step explanation:

Starts with 7x^2 then a term in x then a constant.

4 0

2 years ago

Hey i really need help with this. thank you:))

balandron [24]

Given:

$L=2\dfrac{1}{2}$ ft and $W=3\dfrac{2}{5}$ ft.

$P=2L+2W$

To find:

The value of P.

Solution:

We have,

$P=2L+2W$

Substituting $L=2\dfrac{1}{2}$ and $W=3\dfrac{2}{5}$ , we get

$P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}$

$P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}$

$P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}$

$P=5+\dfrac{34}{5}$

Taking LCM, we get

$P=\dfrac{5(5)+34}{5}$

$P=\dfrac{25+34}{5}$

$P=\dfrac{59}{5}$

$P=11\dfrac{4}{5}$

Therefore, the value of P is $11\dfrac{4}{5}$ ft.

7 0

3 years ago

Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?

ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

$D=6\ cm$

The radius of circle A is

$r=6/2=3\ cm$ -----> the radius is half the diameter

<em>Circle B</em>

$r=18\ cm$

Compare the radius of both circles

$3\ cm< 18\ cm$

$18=6(3)$

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

so

$6^{2}=36$

therefore

The area of circle B is 36 times greater than the area of circle A

8 0

3 years ago

Twice a increased by the cube of a equals b

Kobotan [32]

Twice a increased by the cube of a equals b :

2a + a^3 = b

5 0

3 years ago

What is the area of this figure?

ludmilkaskok [199]

Answer:

$\large\boxed{\large\boxed{42 unit^2}}$

Explanation:

The figure is not a regular hexagon. It is an irregular hexagon.

Please, find attached the picture with the original question and the figure.

You can split the figure into two triangles and one rectangle.

The rectangle has dimensions: 7units × 4units, thus its area is 28 units².

Both the upper triangle and lower triangle have base 7 units and height 2 units.

Hence the area of each triangle is:

$area=(1/2)base\times height$

$area=(1/2)7units\times 2units = 7units^2$

Hence, the area of the hexagon is:

$28units^2+7units^2+7units^2=42units^2$

3 0

3 years ago