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3 years ago

Consider the enlargement of the triangle.

Mathematics

2 answers:

Alina [70]3 years ago

7 0

Answer:

Kyla multiplied the corresponding sides by 2 instead of dividing to find the original.

Step-by-step explanation:

creativ13 [48]3 years ago

7 0

Answer:

Kyla multiplied the corresponding sides by 2 instead of dividing to find the original. just did it

Step-by-step explanation:

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In ΔJKL, the measure of ∠L=90°, the measure of ∠J=25°, and KL = 26 feet. Find the length of LJ to the nearest tenth of a foot.

saul85 [17]

Answer:

55.8 feet

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2 years ago

What is the constant in the expression 9x3 + 3x2 + 4 + 5x?

bogdanovich [222]

Answer:

Step-by-step explanation:

The constant is the lone number, in this case it is 4.

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3 years ago

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Is A) median for town A is 30 which is less than for a town B, 40.

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3 years ago

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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

OleMash [197]

ANSWER

$x=1.39$ to the nearest hundredth.

EXPLANATION

We have the equation,

$0=2x^2+3x-8$

Which can be rewritten as

$2x^2+3x-8=0$

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

$ax^2+bx+c=0$

$a=2,b=3,c=-8$

The quadratic formula is given by;

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We now substitute all the values in to the formula;

$x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}$

We simplify to obtain;

$x=\frac{-3\pm\sqrt{9+64}}{4}$

$x=\frac{-3\pm\sqrt{73}}{4}$

We now split the plus or minus sign to obtain;

$x=\frac{-3-\sqrt{73}}{4}$

This implies that;

$x=-2.89$

$x=\frac{-3+\sqrt{73}}{4}$

This will evaluate to;

$x=1.39$

Hence, the positive solution rounded to the nearest hundredth is

$x \approx 1.39$

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3 years ago

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Let g(x) = sqrt2x/ln(x) find g'(x)

nikklg [1K]

Answer:

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2 years ago