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jonny [76]
3 years ago
14

Help -9x + 3.0 > 6.6 Group of answer choices x 0.4 x 2.4

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

x  0.4

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
How many numbers are opposite to themselves?
snow_tiger [21]

Answer:

all positive numbers and their negatives are opposites. I suppose you could say infinite and zero are also opposites.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
7
Maurinko [17]

Answer:

6(7a + 9b) = 3(14a + 18b)

Step-by-step explanation:

We need to find the equivalent expression for the given expression i.e. 6(7a + 9b).

We can use the distributive property here such that,

a(b+c) = ab + ac

We have, a = 6, b = 7 and c = 9

6(7a + 9b) = 6(7a) + 6(9b)

= 42a + 54b

or taking 3 common from the above expression.

= 3(14a+18b)

Hence, the correct option is (a).

8 0
3 years ago
The coordinates of the midpoint of line GH are M(−132,−6) M ( − 13/2 , − 6 ) and the coordinates of one endpoint are G(−4, 1)
Alecsey [184]

Since, the coordinates of the midpoint of line GH are M(\frac{-13}{2}, -6).

The coordinates of endpoint G are (-4,1)

We have to determine the coordinates of endpoint H.

The midpoint of the line segment joining the points (x_1, y_1) and (x_2, y_2) is given by the formula (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}).

Here, The endpoint G is (-4,1) So, x_1 = -4 , y_1=1

Let the endpoint H be (x_2,y_2)

The midpoint coordinate M is (\frac{-13}{2}, -6).

So, \frac{-13}{2} = \frac{-4+x_2}{2}

{-13} = {-4+x_2}

{-13}+4 = {x_2}

{x_2}=9

Now, -6 = \frac{1+y_2}{2}

-12 = {1+y_2}

y_2= -13

So, the other endpoint H is (-9,-13).

7 0
3 years ago
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