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Setler79 [48]
3 years ago
8

Alan and Samuel each have a 30-year mortgage. Both mortgages were approved at the same time. Alan pays 5 percent interest, while

Samuel only pays 3.5 percent.
If Alan and Samuel are the same age and make the same amount of money, why is Alan paying more in interest?


a) Samuel has a better credit score, so his interest rate is lower.

b) Samuel has more credit cards, so he recieves a better rate.

c) Alan has a better credit score, so his interest rate is higher.

d) Alan has a longer credit history, so he recieves a worse rate.
Mathematics
2 answers:
nevsk [136]3 years ago
7 0

The answer would be c

Vesna [10]3 years ago
7 0

Answer:

a) Samuel has a better credit score, so his interest rate is lower.

Step-by-step explanation:

Alan and Samuel both are same age and make same amount of money.

They both have a 30-year mortgage. But Alan pays 5 percent interest, while Samuel only pays 3.5 percent.

There correct answer here will be - Samuel has a better credit score, so his interest rate is lower.

When a person has a good credit rating, that means he has never defaulted any payment and has always paid his loan on time. He must be a trusted customer for the bank that is why he got a lower interest rate than Alan.

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The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

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\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

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How should I solve this? I tried to but I couldn't get past the quadratic formula.
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First multiply all terms by z
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Then order into standard form
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