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vivado [14]
3 years ago
11

100000000.9996 x 6969781446.913

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

6.9697815e+17 (e+17 means 17 0's at the end of the problem. So, the exact answer would be 6.969781500000000000000000)

Step-by-step explanation:

Hope this helps! :D

Also, if it is no trouble, can I have brainliest? This equation took awhile.

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Instructions: Given the following constraints, find the maximum and minimum values for z.
loris [4]

Answer:

x+3y\leq 0        

x-y\geq 0

1) x+3y=0

x-y=0

-----

4y=0

y=0

x=0

(0,0)

2)(x+3y=0)3

3x-7y=16

3x+9y=0

3x-7y=16\\------\\16y=-16

y=-1

(3,-1)

3)(x-y=0)3

3x-7y=16

3x-3y=16

3x-3y=0

3x-7y=16\\------\\4y=-16

y=-4

x=4

(4,-4)

Z=-x+5y

(0,0):z=0

(3,-1):z=-8

(4,-4):z=-24

Maximum \:Value\: of\: z:0

Minimum\: Value\: of\: z:-24

<u>OAmalOHopeO</u>

8 0
3 years ago
0.5m + 6.4 = 4.9 - 0.1m
BigorU [14]
Solve for m by simplifying both sides of the equation, then isolating the variable.
m = -2.5
5 0
3 years ago
Look at the picture
shusha [124]

Answer:

1) √10 units

A=(-1, 0) let us assume (x1, y1)

B=(2, 1) let us assume (x2,y2)

distance= √(x2-x1)^2 + (y2-y1)^2

=√(2+1)^2 + ( 1-0)^2

=√3^2 + 1^2

= √10 units

3 0
3 years ago
When z=−6, evaluate −2(z+9)−(−5) and −2⋅z−2⋅9+5 to show that −2(z+9)−(−5)=−2⋅z−2⋅9+5
KengaRu [80]

Ignore this, I posted the wrong answer and I don't know how to delete it.

3 0
3 years ago
Read 2 more answers
A Gallup Poll found that 51% of the people in its sample said "yes" when asked, "Would you like to lose weight?" Gallup announce
Nata [24]

Answer:

(a) 95% confidence interval for the percent of all adults who want to lose weight is (48%, 54%) that is between 48% and 54%

(b) to say that we have 95% confidence in this interval means that there is 95% chance that the true percentage of all adults who wants to lose weight falls in this interval.

Step-by-step explanation:

The question is missing, complete question is below:

A Gallup Poll found that 51% of the people in its sample said "yes" when asked, "Would you like to lose weight?" Gallup announced: "With 95% confidence for results based on the total sample of national adults, one can say that the margin of sampling error is ± 3%."

(a) What is the 95% confidence interval for the percent of all adults who want to lose weight?

(b) What does it mean to say that we have 95% confidence in this interval?

Confidence Interval can be calculated using p±ME where

  • p is the sample proportion of national adults who want to lose weight (51%)
  • ME is the margin of sampling error (± 3%)
4 0
4 years ago
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