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zubka84 [21]
3 years ago
10

7x²+3y²-28x-12y=-19

Mathematics
1 answer:
grigory [225]3 years ago
4 0
Complete the square for x and y.

7x^2 + 3y^2 - 28x - 12y = -19

7x^2 - 28x + 3y^2 - 12y = -19

7(x^2 - 4x) + 3(y^2 - 4y) = -19

7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12

7(x - 2)^2 + 3(y - 2)^2 = 21

\dfrac{(x - 2)^2}{3} + \dfrac{(y - 2)^2}{7} = 1
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5 0
2 years ago
Find the values of p and q such that 4x-5-x^2=q-(x+p)^2
Solnce55 [7]

Answer:

p = - 2 , q = - 1

Step-by-step explanation:

Rearrange the left side into standard form

- x² + 4x - 5

Factor out - 1 from - x² + 4x

= - (x² - 4x) - 5

Using the method of completing the square

add/subtract ( half the coefficient of the x- term)² tp x² - 4x

= - (x² + 2(- 2)x + 4 - 4) - 5

= - (x - 2)² - (- 4) - 5

= - (x - 2)² + 4 - 5

= - 1 - (x - 2)²

Comparing to q - (x + p)²

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4 0
3 years ago
Find the difference. Write your answer in scientific notation. (1.5 x 10^4) - (7.6 x 10^3) =​
BabaBlast [244]

Answer:

The answer is 7.4 × 10³ ( or 0.74 × 10⁴).

Step-by-step explanation:

The steps are :

(1.5 × 10⁴) - (7.6 × 10³)

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7 0
3 years ago
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