7x²+3y²-28x-12y=-19

1 answer:

4 0

Complete the square for x and y.

7x^2 + 3y^2 - 28x - 12y = -19

7x^2 - 28x + 3y^2 - 12y = -19

7(x^2 - 4x) + 3(y^2 - 4y) = -19

7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12

7(x - 2)^2 + 3(y - 2)^2 = 21

$\dfrac{(x - 2)^2}{3} + \dfrac{(y - 2)^2}{7} = 1$

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A circle has a radius if 20 centimeters and a central angle that measures 118 degrees. Find the length of the arc defined by thu

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$\textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=20\\ \theta =118 \end{cases}\implies \begin{array}{llll} s=\cfrac{(118)\pi (20)}{180}\implies s=\cfrac{118\pi }{9} \\\\\\ s\approx 41.19~cm \end{array}$