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Verizon [17]
3 years ago
15

On Friday, a bowling alley made $842.72 from lane rentals and $412.38 from the concession stand. On Saturday, their lane rentals

were down by mc024-1.jpg but the concessions increased by mc024-2.jpg. What is the total amount that the bowling alley earned in lane rentals and concessions on Friday and Saturday?
Mathematics
2 answers:
Ivahew [28]3 years ago
7 0

Answer:

The correct answer is A

Step-by-step explanation:

ExtremeBDS [4]3 years ago
6 0
<span>On Friday, a bowling alley made $842.72 from lane rentals and $412.38 from the concession stand. On Saturday, their lane rentals were down by 1/8 but the concessions increased by 1/2 What is the total amount that the bowling alley earned in lane rentals and concessions on Friday and Saturday? A.$1,355.95 B.$1,580.10 C.$1,992.48 D.$2,611.05

lane rentals: 842.72 x (8/8-1/8) = 842.72 x 7/8 = 737.38
concessions: 412.38 x (1 + 1/2) = 412.38 x 1.5 = 618.57

Total: 737.38 + 618.57 = 1,355.95 Choice A.</span>
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Answer:

Step-by-step explanation:

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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