The value of A is RM 205.
Since Billy gave money to a charity over a 20 year period, from Year 1 to Year 20 inclusive, and he gave RM150 in Year 1, RM160 in Year 2, RM170 in year 3, and so on, and Kevin also gave money to the charity over the same 20 years period, but he gave RMA im Year 1 and the amount of money he gave each year increased, forming an arithmetic sequence with common difference RM30, and the total amount of money that Kevin gave over 20 years period was twice the total amount of money that Billy gave, to calculate the value of A the following calculation must be performed:
- Billy = (150 x 20) + 10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 + 100 + 110 + 120 + 130 + 140 + 150 + 160 + 170 + 180 + 190
- Billy = (150 x 20) + 1900
- Billy = 3000 + 1900
- Billy = 4900
- Kevin = (9800 - (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240 + 270 + 300 + 330 + 360 + 390 + 420 + 450 + 480 + 510 + 540 + 570)) / 20
- Kevin = (9800 - 5700) / 20
- Kevin = 4100/20
- Kevin = 205
Therefore, the value of A is RM 205.
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Answer: What is the question????
Answer:
<u>475 runners</u> competed in the Labor Day race.
Step-by-step explanation:
Given:
Last year, 60% of runners who competed in the Labor Day race finished in 1 hour or less. There were 285 runners who finished the Labor Day race in 1 hour or less.
Now, to find the runners competed in the Labor Day race.
Let the runners competed in the Labor Day race be
Rate of runners who competed in the Labor Day race finished in 1 hour or less = 60%.
Number of runners who competed in the Labor Day race finished in 1 hour or less = 285.
Now, to get the runners competed in the Labor Day race we put an equation:
<em>Dividing both sides by 0.60 we get:</em>
Therefore, 475 runners competed in the Labor Day race.
9x = 0, x = 0
x + 6 = 0, x = -6
The solution: x = 0, -6
Answer:
there is no solutions
Step-by-step explanation: