Help! Can anyone Simplify this for me

Mathematics

1 answer:

Tcecarenko [31]3 years ago

5 0

64x $^{6}$ y $^{12}$

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B [2 0] -2 5 What is the determinant of B? Your answer

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Answer:

Step-by-step explanation:

Determinant = ad - bc

$\det\begin{pmatrix} 2 & 0 \\-2 & 5\end{pmatrix} =\begin{vmatrix} 2 & 0 \\-2 & 5\end{vmatrix} = 2\times5 + 0\times2 = 10$

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Use the PACED decision-making process to _____.

Alex_Xolod [135]

Use the PACED decision-making process to make a decision or make a choice. The steps to follow when making a decision can be easily remembered when you use the word PACED:
P - What is the PROBLEM - Why is there a need to make a choice?
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Kitty [74]

Answer: (-2, 5) and (2, -3)

Step-by-step explanation:

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

y - intercept = (0, 1) 2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

$y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\$

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)

see attached - the graphs intersect at two points: (-2, 5) and (2, -3)

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