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bixtya [17]
3 years ago
10

Solve for x. x/2 = -7

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0

Answer:

x = -14

Step-by-step explanation:

x/2 = -7

Multiply each side by 2

x/2*2 = -7*2

x = -14

Paraphin [41]3 years ago
8 0

Answer:

x = -14

Explanation:

x/2 = -7

Simplify

1/2 x = -7

x2

x = -14

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An amusement park the ratio of boys to girls is 4 to 3 if their are 98 children, how many are girls
madam [21]
98 divided by 7 is 14. 14 multiplied by 3 is 42. So there are 42 girls.
7 0
3 years ago
What common denominator can be used to write the left side as one rational expression?
iris [78.8K]

Answer:

10(10+x)

Step-by-step explanation:

7 0
4 years ago
Find the value of x. 2(x-3)-17=13-3(x+2)
Nonamiya [84]
Solve your equation step-by-step.

2(x−3)−17=13−3(x+2)

Simplify both sides of the equation.

2(x−3)−17=13−3(x+2)

Simplify

2x−23=−3x+7

Add 3x to both sides.

2x−23+3x=−3x+7+3x

5x−23=7

Add 23 to both sides.

5x−23+23=7+23

5x=30

Divide both sides by 5.

5x/5 = 30/5

x=6

5 0
3 years ago
Read 2 more answers
PLEASE HELP
Masja [62]

Answer:

y = 50x + 20

Step-by-step explanation:

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }

Use the slope-intercept formula to find the slope.

m = \frac{120 - 20}{2 - 0}

m = \frac{100}{2} = 50

The y-intercept is where the line crosses the y-axis.

3 0
3 years ago
Read 2 more answers
Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95% confidence interval for the
Artemon [7]

Answer:

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 375, \pi = \frac{30}{375} = 0.08

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 - 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.0525

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 + 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.1075

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

4 0
3 years ago
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