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3 years ago

How do you construct a hexagon?

Mathematics

1 answer:

horrorfan [7]3 years ago

5 0

A hexagon has 6 even corners that are connected evenly as shown.

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-104=-8(k+8) <br><br> K = ?<br> Solution please if can?

maksim [4K]

Let's solve this question by step by step.

Layout equation.

−104=−8(k+8)

Step 1: Simplify both sides of the equation.

−104=−8(k+8)

−104=(−8)(k)+(−8)(8)(Distribute)

−104=−8k+−64

−104=−8k−64

Step 2: Flip the equation.

−8k−64=−104

Step 3: Add 64 to both sides.

−8k−64+64=−104+64

−8k=−40

Step 4: Divide both sides by -8.

-8k/-8=-40/-8

The answer for this problem is k=5.

5 0

3 years ago

Please help me now plz <br> I will mark you brainliest

olga2289 [7]

Answer:

? = 4.28

Step-by-step explanation:

We know that tan theta = opp side / adjacent side

tan 35 = 3 / ?

Multiply each side by ?

? tan 35 = 3

Divide each side by tan 35

? = 3/tan 35

?= 4.28444402

To the nearest hundredth

? = 4.28

5 0

3 years ago

The shapes below are mathematically similar

s2008m [1.1K]

Answer:

5 cm is the answer brochacho

7 0

3 years ago

If two angles are complementary, which is the sum of their measurements?

Anna [14]

Answer: a complimentary angle measures 90 degrees. The measure of 2 complimentary angles would be 2x90=180

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

3 years ago