If you can, please explain the step by step process to finding the answer.
1 answer:
Answer:
20% peanuts are there in the mixture of nuts.
Step-by-step explanation:
Total weight of the mixture =25 lbs(10+15)
In the 25 lbs mixture of nuts, 68 % is peanuts, therefore finding the total weight of peanuts.
68 % of 25 lbs= 17 lbs.
There is a total 17 lbs of peanuts in the mixture .
15 lbs of peanuts was exclusively added, therefore the rest 2 lbs must have come from the mixture of nuts.
Therefore, there is a total of 2 lbs of peanuts in 10 lbs of mixture of nuts.
=20 %
20% peanuts are there in the mixture of nuts.
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You can factor this out by thinking of the factors of 56 that have a sum of -1. 7 and 8 are factors of 56 and to get a sum of -1, 8 should be negative. 7 + -8 = -1
So
factored out is (y+7x)(y-8x)
We can check this using FOIL
F = (y)(y) =
O = (y)(-8x) = -8xy
I = (7x)(y) = 7xy
L = (7x)(-8x) =
Combine like terms
So
We can check this using FOIL
F = (y)(y) =
O = (y)(-8x) = -8xy
I = (7x)(y) = 7xy
L = (7x)(-8x) =