Factor completely y^2-xy-56x^2

Mathematics

2 answers:

ki77a [65]3 years ago

5 0

Answer: I got (y-8x)(y-7x) by factoring out the factors of 56, that have a sum of -1.

8 and 7 are factors of 56 when you multiply them and to get a sum of -1, 8 should change to negative. 7 + -8 = -1

olga2289 [7]3 years ago

3 0

You can factor this out by thinking of the factors of 56 that have a sum of -1. 7 and 8 are factors of 56 and to get a sum of -1, 8 should be negative. 7 + -8 = -1

So $y^{2} - xy - 56x^{2}$ factored out is (y+7x)(y-8x)

We can check this using FOIL
F = (y)(y) = $y^{2}$
O = (y)(-8x) = -8xy
I = (7x)(y) = 7xy
L = (7x)(-8x) = $-56x^{2}$
$y^{2} - 8xy + 7xy - 56x^{2}$ Combine like terms
$y^{2} - xy - 56x^{2}$

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Eduardwww [97]

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