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mixas84 [53]
3 years ago
6

Factor completely y^2-xy-56x^2

Mathematics
2 answers:
ki77a [65]3 years ago
5 0

Answer: <em> </em>I got (y-8x)(y-7x) by factoring out the factors of 56, that have a sum of -1.

8 and 7 are factors of 56 when you multiply them and to get a sum of -1, 8 should change to negative. 7 + -8 = -1

olga2289 [7]3 years ago
3 0
You can factor this out by thinking of the factors of 56 that have a sum of -1. 7 and 8 are factors of 56 and to get a sum of -1, 8 should be negative. 7 + -8 = -1

So y^{2} - xy -  56x^{2} factored out is (y+7x)(y-8x)

We can check this using FOIL
F = (y)(y) = y^{2}
O = (y)(-8x) = -8xy
I = (7x)(y) = 7xy 
L = (7x)(-8x) = -56x^{2}
y^{2} - 8xy + 7xy - 56x^{2} Combine like terms
y^{2} - xy - 56x^{2}
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15z + 728 = 28z

28z - 15z = 728     .......... rearranging above equation

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6 0
3 years ago
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: Below are two expressions. Simplify each and then choose the statement that is true.
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Vladimir79 [104]

Answer: 241

Step-by-step explanation:

This is a simple problem when using Pascal's triangle. First you look at 1 - 3, what is the difference in these 2 numbers? Its 2, then you look at 3 and 11, the difference is 8, then 11 and 35, the difference is 24. If you keep doing this you get; 2 8 24 64 142. Next you find out how these numbers are different. In the end you keep doing this until you get to the triangles point or the differences converge.

                                          1      3      11      35     99      <u>241</u>

                                             2      8     24       64    142

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In the end we get 14 but there is no difference in the numbers so we cant go any farther. Hope this helps!

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