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3 years ago

Please, help me with my homework?

Mathematics

2 answers:

ivann1987 [24]3 years ago

5 0

Answer:

yea what do you need help with?

Step-by-step explanation:

lys-0071 [83]3 years ago

4 0

Answer:

I'd be happy to help.

Step-by-step explanation:

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Alex wants to cover his wall

alexandr1967 [171]

Answer: A = π r2

r=8 and 8 squared is 64 and 64×3.14=200.96 or rounded to the nearest whole number it would be 201

Step-by-step explanation: brainliest please?

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2 years ago

How do you write 4.04bas a percent?

user100 [1]

It would be 404%

Hope this helps!

6 0

3 years ago

Use the following trinomial to answer the questions. x^2-6x-27 When going through the process of determining the factors, the tw

Sauron [17]

Answer:

The factors are 3 and -9

Step-by-step explanation:

The given trinomial is $x^2-6x-27$ .

We need to find two factors. We know that,

3(9) = 27

So,

$x^2-6x-27$ can be written as :

$x^2+3x-9x-27$ as two factors add up to get -6 and multiply to get -27.

Hence, the factors are 3 and -9.

5 0

3 years ago

How can I solve for c

s2008m [1.1K]

Answer:

$(\frac{2}{5})c$

8 0

3 years ago

Read 2 more answers

Given f(x) =

sergejj [24]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = \left\{ \begin{array}{ll} 2\cos(\pi x) \text{ for } x \leq -1 \\ \\ \displaystyle \frac{2}{\cos(\pi x)}\text{ for } x > -1 \end{array} \right.$

And we want to find:

$\displaystyle \lim_{x\to -1}f(x)$

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

$\displaystyle \lim_{x\to-1^-}f(x)$

Since we are approaching from the left, we will use the first equation:

$\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)$

By direct substitution:

$=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2$

Right-Hand Limit:

$\displaystyle \lim_{x\to -1^+}f(x)$

Since we are approaching from the right, we will use the second equation:

$=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}$

Direct substitution:

$\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2$

So, we can see that:

$\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2$

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

$\displaystyle \lim_{x \to -1}f(x)=-2$

Our answer is A.

8 0

3 years ago