The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Given: k(x) = 5x - 1, h(x) = -3x - 1
We need to find the point(if any) at which these two lines k and h meets.
To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.
Therefore, k(x) = h(x)
=> 5x - 1 = -3x - 1
=> 8x = 0
=> x = 0
k(x=0) = 5 * 0 - 1 = -1
Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Know more about "point of intersection" problems here: brainly.com/question/16929168
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The answer is both triangles A and D
Hope this helps :)
Answer:
B
Step-by-step explanation:
Opposite is 1.9
The answer this problem is -247
Hello!
A rhombus is any quadrilateral that has congruent side lengths. A square has all four sides the same length, so a square can be considered a rhombus.
I hope this helps!
