Need help with question 5) & 6) TIA☺️
1 answer:
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From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Answer:
the length of RS to the nearest tenth of a foot is 240.6ft
Answer:
DNE
Step-by-step explanation:
The the given table, we have;
As x approaches -14 from the left, at x = -14.001, p(x) = 1.96
As x approaches -14 from the right, at x = -13.999, p(x) = 1.97
The value of p(x) when x = -14 is = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;
Does Not Exist, DNE.