Answer:

tep-by-step explanation:
In order to find the integral:
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we can do the following substitution:
Let's call

Then

which allows us to do convert the original integral into a much simpler one of easy solution:

Therefore, our integral written in terms of "x" would be:

Inside of the triangle must = 180. Let angle '4' = x. x + 45 + 47 = 180. Combine like terms, x + 92 = 180. Subtract 92 on both sides, x = 88.
Now angle '4' and angle '3' must equal 180 because they are on the same plane. Let angle '3' = y. y + 88 = 180. Subtract 88 on both sides, y = 92.
So Angle 4 is 88 degrees and Angle 3 is 92 degrees.
Abcdefghijklmnopqrstuvwxy and z now which letter(s) did I repeat ?
Since there are 3 feet to a yard,26 feet= 26/3 yards =8 2/3 yards