Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.
Thus, the length of fencing needed is given by
P = x + 2y
The area of the rectangle is given by xy,
i.e.

Substituting for y into the equation for the length of fencing needed, we have

For the amount of fencing to be minimum, then

Now, recall that

Thus, the length of fencing needed is given by
P = x + 2y = 24 + 2(12) = 24 + 24 = 48.
Therefore, 48 feets of fencing is needed to enclose the garden.
Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) =
then h(12) =
so h(12) = 144
Answer:
2*2*3*5
Step-by-step explanation:
We need to factor 60 until it is prime numbers
60 = 12*5 5 is prime 12 is not
=3*4 *5 3,5 prime 4 is not
= 3 *2*2 *5 2,3,5 are prime
Rearranging the order
=2*2*3*5
Answer:
38.60mm
Step-by-step explanation:
Step one:
Given data
We are given that the dimension of the triangles are length 23 mm and 31 mm
Let us assume that the triangle is a right angle triangle
Step two:
Applying the Pythagoras theorem we can find the third as

square both sides
z= √ 1490
z= 38.60mm
Hence a possible dimension of the third side is 38.60mm