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3 years ago

What is the domain of the function shown in the graph below?

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

Domain: (+∞, -∞)

Step-by-step explanation:

Domain = x value

hope it helps

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You plan on buying new flooring for your bedroom. Your bedroom is a rectangle that is 12.7 ft. by 14.25 ft. How many square feet

joja [24]

Answer:

180.975 square feet

Step-by-step explanation:

est: 181 square feet

4 0

3 years ago

374x+3=2995 ME GIVE BRAIN I MUST DO MY HOMEWORK you lifesaver...

Kaylis [27]

Hi there!

x=8

1.Subtract the answer with the 3 / subtract the terms:

$2995-3=2992$

2.Divide the two terms:

$2992*374=x$

Therefore, x=8

3 0

3 years ago

Let f(x) and g(x) be polynomials as shown below. Which of the following is true about f(x) and g(x)? f(x) and g(x) are not close

Mrrafil [7]

Answer:

f(x) and g(x) are closed under multiplication because when multiplied, the result will be a polynomial.

Step-by-step explanation:

The set of all polynomials is closed under addition, subtraction, and multiplication, because performing any of these operations on a pair of polynomials will give a polynomial result.

Comment on the question

The wording is a bit strange, because f(x) and g(x) are elements of a set (of polynomials), so cannot be said to be "closed." "Closed" is a property of a set with respect to some function, it is not a property of an element of the set.

6 0

3 years ago

Find the midpoint of X (26,56) and Y (26,1)

Svetradugi [14.3K]

Answer:

(26, $\frac{57}{2}$ )

Step-by-step explanation:

Hi there!

We are given the coordinates (26, 56) and (26, 1)

We want to find the midpoint of these two points

The midpoint can be found using the formula $(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})$ , where $(x_1, y_1)$ & $(x_2, y_2)$ are points

We have 2 points, which is what we need to find the midpoint, but let's label the values of the points to avoid confusion and mistakes when actually calculating

$x_1=26\\y_1=56\\x_2=26\\y_2=1$

Now substitute these values into the formula.

$(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})$

$(\frac{26 + 26}{2} , \frac{56+ 1}{2})$

Add the numbers together

$(\frac{52}{2} , \frac{57}{2})$

Divide

(26, $\frac{57}{2}$ )

Hope this helps!

4 0

2 years ago

Read 2 more answers

How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?

kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = $\frac{6!}{5!*1!}=6$

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = $\frac{7!}{5!*2!}=21$

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = $\frac{8!}{5!*3!}=56$

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0

3 years ago

Read 2 more answers