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dolphi86 [110]
3 years ago
15

Four years ago, Jane was twice as old as Sam. Four years on from now, Sam will be 3/4 of Jane's age. How old is Jane now?

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0
How old is sam? We need that first
Genrish500 [490]3 years ago
5 0
12 is Jane's Age now. 8 is Jame's age now 
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4.2

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A rectangular yard has dimensions 10 meters by 8 meters. In the middle of the yard is a rectangular pond of 8 square meters, lea
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hahahaha i had this same question in my grade

8 0
3 years ago
Find the tangent of angle A (giving brainliest and thanks to all!)
Shtirlitz [24]

Answer:

Option B, 8 / 6

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3 0
3 years ago
Please help me, i have been on this problem for 45 minutes.
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Answer:

Step-by-step explanation:

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8 0
3 years ago
In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho
Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be \frac{42}{7} C^{\circ}.


Additionally, this can be solved by equations:

\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}

1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}

\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}

\dfrac{42}{7} = x


By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

6 0
3 years ago
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