Which relation is a function?

Please answer my question, and if you can please provide an explanation so I can learn from it. 50 POINTS.

gayaneshka [121]

Answer: -4x - y = -50 (second option)

Step-by-step explanation: The only way lines won't intersect is if they're parallel. Parallel lines have the same slope --> the line must have a slope of -4x.

Option 1:

y = 4x - 200 (add 4x to both sides)
Different slope.

Option 2:

-y = 4x - 50 (add 4x to both sides)
y = -4x + 50 (divide by -1)
Same slope.

Option 3:

-y = -4x - 200 (subtract 4x from both sides)
y = 4x + 200 (divide by -1)
Different slope.

Option 4:

-y = -4x - 50 (subtract 4x from both sides)
y = 4x + 50 (divide by -1)
Different slope.

8 0

3 years ago

Read 2 more answers

I'll send a pic of the questions

Gnoma [55]

The initial expression is:

$-10+\frac{r}{5}=1$

So we can solve for r so:

$\begin{gathered} \frac{r}{5}=1+10 \\ r=11\cdot5 \\ r=55 \end{gathered}$

7 0

1 year ago

Need help please (: Show how to apply the order of operation rules as you simplify the following expression

Gwar [14]

Apply in this order Ι-15Ι - 33÷11= 15-3=12

Good luck!!!

7 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

Of all the species in the world, 3 out of every 5 are insects. What percentage of species are insects?

Anni [7]

Answer:

perhaps 60%?

Step-by-step explanation:

3 0

3 years ago