All categories

3 years ago

How to convert 2.4 to radical form

1 answer:

6 0

To convert 2.4 into a radical you have to write the equation;
2.4=√x; then you square both sides, to get x by itself, resulting in 5.8; and then you have to write; "2.4 in radical form is the square root of 5.8

You might be interested in

Nick has tennis practice every sixth day. Mark has tennis practice every 4th day. On July 31st they both had tennis practice. Wh

Montano1993 [528]

Nick has tennis practice every sixth day = 6

Mark has tennis practice every 4th day = 4

They both had tennis practice on = 31st July

We have to find when will be the next time that they both have practice on the same day?

For this, we will find the LCM of 4 and 6

So, LCM of 4 and 6 is 12.

So, it will be 12 days after 31st July, that they will practice on the same day.

So it is 12th August.

3 0

3 years ago

A student's grade depends on her score on four equally-weighted exams. Her average on the first three exams is 92. What must she

Sergeeva-Olga [200]

3x92 = 276 (first 3 exams)
average of at least 90 (90 x 4 = 360)

360 - 276 = 84

Answer
<span>she needs to score at least 84 on the fourth exam </span><span>in order to guarantee a final average of at least 90</span>

4 0

2 years ago

What’s 4930 x 184 equal

Flura [38]

Answer:

907120

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A,B and C are the vertices of one triangle.

dsp73

Answer:

Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is $\frac{AD}{DB}=\frac{AE}{EC}$ , then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates= $(\frac{4+2}{2},\frac{6-2}{2})=(3,2)$ and Mid Point E has coordinates= $(\frac{4-2}{2},\frac{6-4}{2})=(1,1)$

Now, AD= $\sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}$

DB= $\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}$

AE= $\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}$

EC= $\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}$

Now, $\frac{AD}{DB}=\frac{AE}{EC}$

= $\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}$

Hence, $\frac{AD}{DB}=\frac{AE}{EC}$

Thus, By basic proportionality theorem, DE is parallel to BC.

4 0

3 years ago

Read 2 more answers

The variable z has a standard normal distribution. find the value z such that the event z > z has proportion 0.08. z = –1.41

andrezito [222]

The appropriate choice is z = 1.41.

The empirical rule tells you 68% of the distribution is within 1 standard deviation, so p(z > 1) ≈ 0.17. This means the z value is more than 1 for the probability to drop to 0.08. The only choice that is greater than 1 is 1.41. (The number is actually about 1.40507.)

3 0

2 years ago