Answer:
no solutions
Step-by-step explanation:
b-9-b=-18
Combine like terms
0b -9 = -18
-9 = -18
This is never true, so there are no solutions
122
286-42=144
144\2=122
122(peter)+164(malco)=286(total weight)
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
48 inch
Step-by-step explanation:
Answer:
1.) 16.5
2.) 24.2 ft
3.) 10.8 ft
Step-by-step explanation:
1.) So first you need to use Heron's formula
S = (A + B + C)/2
So
S = (17 + 17 + 8)/2
S = 21
Now
Area =
So
So the Area is equal to 66.1
Now to find the height we use the Area of the triangle formula
A = 1/2 B*H
66.1 = 1/2(8) * H
66.1 = 4H
H = 16.525
So the height of the triangle is 16.5 units tall
2.) For this question you just use the Pythagorean theorem.
a² + b² = c²
So 22² + 8² = c²
484 + 64 = c²
548 = c²
= c
c = 24.1660919472 ft
So the length of the wire is 24.2 ft long
3.) Again this is the Pythagorean theorem.
a² + b² = c²
So 10² + 4² = c²
100 + 16 = c²
116 = c²
= c
c = 10.7703296143 ft
So the length of the banner is 10.8 ft long