Answer:
8.212°
Step-by-step explanation:
Hypotenuse^2=base^2+perp^2
(8)^2=(7)^2+(perp)^2
64=49+(perp)^2
64/49=perp^2
1.306=perp^2
Now taking sq root on both sides
Perp=√1.306
Perp=1.142
Sin C=opposite/hypotenuse
Sin C=1.142/8
Sin C=0.14285
C=Sin^-1 0.14285
C=8.212°
recall d = rt, distance = rate * time.
let's say airplane A is going at a rate of "r", therefore airplane B is moving faster, at a rate of "r + 80".
now, after 3 hours, both planes have been travelling for 3 hours each, and say if A has covered "d" miles, then B has covered the slack of 2490 - d.
![\bf \leftarrow \underset{A}{\stackrel{r}{\rule[0.22em]{8em}{0.25pt}}}dallas\underset{B}{\stackrel{r+80}{\rule[0.22em]{18em}{0.25pt}}}\to \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ plane~A&d&r&3\\ plane~B&2490-d&r+80&3 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cleftarrow%20%5Cunderset%7BA%7D%7B%5Cstackrel%7Br%7D%7B%5Crule%5B0.22em%5D%7B8em%7D%7B0.25pt%7D%7D%7Ddallas%5Cunderset%7BB%7D%7B%5Cstackrel%7Br%2B80%7D%7B%5Crule%5B0.22em%5D%7B18em%7D%7B0.25pt%7D%7D%7D%5Cto%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20plane~A%26d%26r%263%5C%5C%20plane~B%262490-d%26r%2B80%263%20%5Cend%7Barray%7D)
Answer: C
Step-by-step explanation:
the right answer to the question is catch me on the root mean square velocity of gas molecule when measured by galvanometer to produce circular egg in the presence of light under blanket.
Answer:
4
Step-by-step explanation:
RS + ST = RT
=> 3x-8 + x = 2x
4x - 8 = 2x
Subtract 2x from both the sides,
4x - 2x - 8 = 0
2x - 8 = 0
Add 8,
2x = 8
Divide by 2,
x = 8/2 = 4
Length of line segment ST = x = 4
