Answer:
He would have a very soggy picture!
OR if you mean the pitcher holds one twelvth of a gallon, he will have 9/12 or 3/4 of a gallon.
OR if you mean the pitcher holds two twelvths of a gallon, he ends up with 9 × 1/6 which is one and a half gallons.
Step-by-step explanation:
Spelling is important! A "picture" could be a drawing, a photograph, or a painting.
"Pitcher" could be a container for pouring liquids or a player who pitches the ball in a baseball game.
I know you wanted math help, but it is difficult to answer if I can't tell whether "to" meant "two" or he filled the pitcher to pour twelvths.
This may help:There are

gallons of lemonade.
Two friends share the lemonade.
What fraction of the lemonade does each friend receive?
To solve you do kcf or keep change flip.
You keep

and change division to multiplication.
Then

is changed to

<span>The answer would be </span>

Hope That Helps!
325.81
It is correct im sure of it
Answer:
(a)Length =2 feet
(b)Width =2 feet
(c)Height=3 feet
Step-by-step explanation:
Let the dimensions of the box be x, y and z
The rectangular box has a square base.
Therefore, Volume of the box
Volume of the box

The material for the base costs
, the material for the sides costs
, and the material for the top costs
.
Area of the base 
Cost of the Base 
Area of the sides 
Cost of the sides=
Area of the Top 
Cost of the Base 
Total Cost, 
Substituting 

To minimize C(x), we solve for the derivative and obtain its critical point
![C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2](https://tex.z-dn.net/?f=C%27%28x%29%3D%5Cdfrac%7B0.6x%5E3-4.8%7D%7Bx%5E2%7D%5C%5CSetting%20%5C%3AC%27%28x%29%3D0%5C%5C0.6x%5E3-4.8%3D0%5C%5C0.6x%5E3%3D4.8%5C%5Cx%5E3%3D4.8%5Cdiv%200.6%5C%5Cx%5E3%3D8%5C%5Cx%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
Recall: 
Therefore, the dimensions that minimizes the cost of the box are:
(a)Length =2 feet
(b)Width =2 feet
(c)Height=3 feet