Answer:
m = -6
Step-by-step explanation:
3m = 2(m - 3)
Distribute
3m = 2m - 6
Subtract 2m from each side
3m -2m = 2m-2m -6
m = -6
Answer:
<h3>
A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>
Step-by-step explanation:
H = 2x+6 - the hight
3H = 3(2x+6) - triple the hight
3H-5 = 3(2x+6) - 5 - five less than triple the height
Area of triangle: A = 0.5BH
B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13
H = 2x+6
So:
A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78
A = 6x² + 49x + 78
Answer:
12
Step-by-step explanation:
Answer:
no solution
Step-by-step explanation:
hello

this is always false so there is no solution
You need at least 2 congruent angles , or 3 proportional sides , or 2 proportional sides and 1 congruent angle to prove that 2 triangles are similar.
I presume that there should be a picture attached to this question , but if you only have 1 side in proportion ( x ) , you cannot prove the similarity of two triangles.
But if there already were two proportional sides or 1 proportional side and one congruent angle , you can prove they are similar if x = 48
Hope it helps