Answer: 12 yearly admissions and 38 single admissions
Step-by-step explanation:
Let x be yearly membership
Let y be single admission
x+y=50 --> # of tickets sold
35.25x+6.25y=660.50 --> $ of tickets
Use elimination method to solve (multiply equation 1 by -3525 and equation 2 by 100)
-3525x-3525y=-176250
+ 3525+625y=66050
-----------------------------------
-2900y=-110200
y=38
Substitute y=38 into equation 1
x+38=50
x=12
Therefore, 12 yearly admissions and 38 single admissions were sold
Answer:
AC = BC = 5
AB = 5√2
∠A = ∠B = 45
∠A = 90
Step-by-step explanation:
AC = 5 ( Reason : 5 squares are present in between A and C )
Similarly,
BC = 5
<u>By Pythagoras theorem</u>,
(AB)² = (AC)² + (BC)²
= 5² + 5²
= 2 * 5²
(AB)² = 2 * 5²
AB = 5√2
Since, sides AC and BC are equal,
∠A = ∠B = 45
Since, AC is perpendicular to BC,
∠A = 90
Answer:
Total tickets = 70
Total cost = $550
Adult's ticket = $9
Child's ticket = $5
Difference = 9 - 5 = $4
Assume all 70 are child's tickets
5 x 70 = 350
But the total cost was 550
550 - 350 = $200
The $200 must have come from Adult's tickets, which has a difference of $4.
200 ÷ 4 = 50
So there are 50 adult's tickets.
70 - 50 = 20
And there are 20 child's tickets.
Hope this helps - Itz.Jordan
Answer:
<h3>
x = 27°</h3>
Step-by-step explanation:
2x + 2x + 72° = 180°
4x = 108°
x = 27°
