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3 years ago

I really need help fast what is the slope please

Mathematics

2 answers:

Anna35 [415]3 years ago

7 0

Answer:

Step-by-step explanation:

but not sure

ExtremeBDS [4]3 years ago

6 0

Answer:

bottom line 6,2

top line 6,6 or -6,6

Step-by-step explanation:

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Simplify 4-8÷2+3 <br><br> please help

kenny6666 [7]

Answer:

4-8÷2+3=3

Step-by-step explanation:

Divide the numbers: 8/2=4

return to the problem: 4-4+3=3

Answer: 3

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4 years ago

Read 2 more answers

If there are 68.8 letters to be mailed if 3 children have to mail them how much does each person have to mail?

irakobra [83]

Each kid will have to mail about 22 letters.

68.8 divided by 3 = 22.93

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3 years ago

Mean birthweight is studied because low birthweight is an indicator of infant mortality. A study of babies in Norway published i

goldenfox [79]

Answer:

Step-by-step explanation:

Download docx

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3 years ago

There are 12 girls and 8 boys in Ms. Sander’s class. Each day, she randomly asks one student to take attendance. In 180 school d

Virty [35]

12 x times 8 equals 96 and 180 subtracted by 96 equals 84

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4 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$

Therefore, the total outcomes for drawing straight are:

$N_S\;=\;({}^{4}C_1)*({}^{4}C_1)^5\;=\;10240$

Thus, the probability of getting a straight hand is:

$P(b)\;=\;\frac{N_S}{N_T}\\\\P(b)\;=\;\frac{10240}{2598960}\\\\P(b)\;=\; 0.0039$

7 0

3 years ago