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storchak [24]
2 years ago
6

(5x-1)(3x+2)(9x-4) simply

Mathematics
2 answers:
dimaraw [331]2 years ago
8 0

Answer:

135x^3 + 3x^2 - 46x + 8.

Step-by-step explanation:

(5x-1)(3x+2)(9x-4)

= (5x - 1)(27x^2 + 18x - 12x - 8)

=  (5x - 1)(27x^2 + 6x - 8)

= 5x(27x^2 + 6x - 8) - 1(27x^2 + 6x - 8)

= 135x^3 + 30x^2 - 40x - 27x^2 - 6x + 8

= 135x^3 + 3x^2 - 46x + 8.

xz_007 [3.2K]2 years ago
4 0

Step-by-step explanation:

= ( 5x - 1 ) ( 3x + 2 ) ( 9x - 4 )

= 5x ( 3x + 2 ) - 1 ( 3x + 2 ) ( 9x - 4 )

= 15x² + 10x - 3x - 2 ( 9x - 4 )

= ( 15x² + 7x - 2 ) ( 9x - 4 )

= 15x² ( 9x - 4 ) + 7x ( 9x - 4 ) - 2 ( 9x - 4 )

= 135x³ - 60x² + 63x² - 28x - 18x + 8

= 135x³ + 3x² - 46x + 8

...

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Luke can paint 91 portraits in 7 weeks. What is<br>has average rate of painting portraits per week?​
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Simplify the complex numbers using de Moivre's Theorem and match them with their solutions.
alexandr1967 [171]

For the numbers in a+bi form, convert to polar form:


1+i=\sqrt2\dfrac{1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)

By DeMoivre's theorem,

(1+i)^5=(\sqrt2)^5\left(\cos\dfrac{5\pi}4+i\sin\dfrac{5\pi}4\right)=4\sqrt2\dfrac{-1-i}{\sqrt2}=-4-4i


-1+i=\sqrt2\dfrac{-1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac{3\pi}4+i\sin\dfrac{3\pi}4}\right)

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\sqrt3+i=2\dfrac{\sqrt3+i}2=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)

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For the numbers already in polar form, DeMoivre's theorem can be applied directly:


2\left(\cos20^\circ+i\sin20^\circ\right)^3=2\left(\cos60^\circ+i\sin60^\circ\right)=2\dfrac{1+i\sqrt3}2=1+i\sqrt3


2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)^4=2(\cos\pi+i\sin\pi)=-2


At second glance, I think the 2s in the last two numbers should also be getting raised to the 3rd and 4th powers:


\left(2(\cos20^\circ+i\sin20^\circ)\right)^3=8\left(\cos60^\circ+i\sin60^\circ\right)=4+4\sqrt3

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4 0
3 years ago
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Step-by-step explanation:

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Answer:

Step-by-step explanation:

C=$200

B=175 frisbees to sell

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hope this helps. :D

5 0
3 years ago
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