Which shape has the same volume as the given prism?

50 points!!! please have serious answers

Darina [25.2K]

Median: Put the list in order from least to greatest.

$20, $20, $23.50, $25, $26.50

$20, $23.50, $25

$23.50 is the median. I took one from each side until I had one left.

Mean: Get the sum of them all and then divide by the number of earnings ( in this case )

$25 + $26.50 = $51.50 $51.50 + $20 = $71.50 $71.50 + $23.50 = $95

$95 + $20 = $115 $115/5 = $23

$23 is the mean.

Mode: Is the one that finds the frequency or in lamen terms it is the number which appears most often.

There's no steps for finding the expect counting how many times that number appeared.

$20 is the mode.

4 0

3 years ago

A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now

olga_2 [115]

Answer:

1) 288.8 km due North

2) 144.9 km due East

3) 323.1 km

4) 207°

Step-by-step explanation:

Bearing: The angle (in degrees) measured clockwise from north.

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Cosine rule

$c^2=a^2+b^2-2ab \cos C$

where a, b and c are the sides and C is the angle opposite side c

-----------------------------------------------------------------------------------------------

Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

Question 1

To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

$\implies \sf \cos(75^{\circ})=\dfrac{y}{150}$

$\implies \sf y=150\cos(75^{\circ})$

$\implies \sf y=38.92285677$

Then add it to the first portion of the journey:

⇒ 250 + 38.92285677... = 288.8 km

Therefore, the ship is now 288.8 km due North.

Question 2

To find how far East the ship is now, find the measure of the long leg of the right triangle (labelled x on the attached diagram):

$\implies \sf \sin(75^{\circ})=\dfrac{x}{150}$

$\implies \sf x=150\sin(75^{\circ})$

$\implies \sf x=144.8888739$

Therefore, the ship is now 144.9 km due East.

Question 3

To find how far the ship is from its starting point (labelled in red as d on the attached diagram), use the cosine rule:

$\sf \implies d^2=250^2+150^2-2(250)(150) \cos (180-75)$

$\implies \sf d=\sqrt{250^2+150^2-2(250)(150) \cos (180-75)}$

$\implies \sf d=323.1275729$

Therefore, the ship is 323.1 km from its starting point.

Question 4

To find the bearing that the ship is now from its original position, find the angle labelled green on the attached diagram.

Use the answers from part 1 and 2 to find the angle that needs to be added to 180°:

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{Total\:Eastern\:distance}{Total\:Northern\:distance}\right)$

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{150\sin(75^{\circ})}{250+150\cos(75^{\circ})}\right)$

$\implies \sf Bearing=180^{\circ}+26.64077...^{\circ}$

$\implies \sf Bearing=207^{\circ}$

Therefore, as bearings are usually given as a three-figure bearings, the bearing of the ship from its original position is 207°

8 0

2 years ago

Read 2 more answers

The total mass of 6 chairs is 33 kilograms. Each chair has the same mass. What is the mass, in grams, of each chair

valina [46]

33000 grams is the mass

7 0

4 years ago

MAKE T THE SUBJECT OF FORMULA G=T+3/7

kaheart [24]

Step-by-step explanation:

G= T+3/7

G-3/7=T

T= G-3/7

6 0

2 years ago

According to a legend, the Chinese Emperor Yu-Huang saw a magic square on the back of a turtle. In a magic square, the numbers i

Oksana_A [137]

Answer:

The ones in red are my answers and the one in black is given

Step-by-step explanation:

I hope it helps

6 0

3 years ago