Find the perimeter. Note it is a parallelogram. Opposite sides are the same measurement.
(4x - 5) + (4x - 5) + (3x + 9) + (3x + 9)
Simplify. Combine like terms
8x - 10 + 6x + 18
14x + 8
14x + 8 is your answer
hope this helps
ANSWER
The points (1,2) and (7,2) lie on the given curve.
EXPLANATION
The given parametric equations are:

and

We make t the subject in the first equation to obtain:

We substitute this into the second equation to get:

When x=1,

When x=2

When x=7,

Therefore the points (1,2) and (7,2) lie on the given curve.
Answer:
Common ratio = 1/2 and first term = 384
or common ratio = -1/2 and first term = -384.
Step-by-step explanation:
T6/T4 = r^5 / r^3 where r = the common ratio and T6 and T4 are 6th and 4th terms
r^5 / r^3 = 12/48
r^2 = 1/4
so r = +/- 1/2.
The 4th term = a r^3 where a = first term.
If r = 1/2:-
48 = a *(1/2)^3 = a/8
a = 8*48
= 384.
if r = -1/2, then a = -384
<h3>
Answer: 9.03</h3>
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Explanation:
For now, focus solely on triangle HGF.
We'll need to find the measure of angle F.
Use the law of cosines
f^2 = g^2 + h^2 - 2*g*h*cos(F)
(4.25)^2 = 8^2 + 6^2 - 2*8*6*cos(F)
18.0625 = 100 - 96*cos(F)
18.0625-100 = -96*cos(F)
-81.9375 = -96*cos(F)
cos(F) = (-81.9375)/(-96)
cos(F) = 0.853515625
F = arccos(0.853515625)
F = 31.403868 degrees approximately
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Now we can move our attention to triangle DEF.
We'll use the angle F we just found to find the length of the opposite side DE, aka side f.
Once again, we use the law of cosines.
f^2 = d^2 + e^2 - 2*d*e*cos(F)
f^2 = (4.75+8)^2 + (11+6)^2 - 2*(4.75+8)*(11+6)*cos(31.403868)
f^2 = 81.563478
f = sqrt(81.563478)
f = 9.031250 approximately
Rounding to two decimal places means we get the final answer of DE = 9.03
Answer: 62 feet approximately.
Step-by-step explanation:
1. Based on the information given in the problem, you can draw a right triangle as the one shown in the image attached, where the height of the tent is represented with
. Therefore, you can calculate it as following:

Where:

2. Substitute values and solve for
, then the height of the circus tent is:

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