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WINSTONCH [101]
3 years ago
6

Pllls help i will make you brainliest How does the graph of y = ax^2 compare to the graph of y = x^2? plls make it a short answe

r response
Mathematics
1 answer:
expeople1 [14]3 years ago
3 0
Y = x^2 is the parent f(x) of y = ax^2.

If a is unspecified, it is defaulted to 1.
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Alright bois i need assistance Whoever gets it right gets Brainliest Answer
Ahat [919]

Find the perimeter. Note it is a parallelogram. Opposite sides are the same measurement.

(4x - 5) + (4x - 5) + (3x + 9) + (3x + 9)

Simplify. Combine like terms

8x - 10 + 6x + 18

14x + 8

14x + 8 is your answer

hope this helps

6 0
4 years ago
Which points are on a plane curve described by the following set of parametric equations?
Vlad1618 [11]

ANSWER

The points (1,2) and (7,2) lie on the given curve.

EXPLANATION

The given parametric equations are:

x = 3t + 4

and

y = 2 {t}^{2}

We make t the subject in the first equation to obtain:

t =  \frac{x - 4}{3}

We substitute this into the second equation to get:

y =2{(\frac{x - 4}{3} )}^{2}

When x=1,

y = 2 {(\frac{1 - 4}{3} )}^{2}  = 2

When x=2

y =2{(\frac{2- 4}{3} )}^{2}  =  \frac{8}{9}

When x=7,

y =2{(\frac{7 - 4}{3} )}^{2}  = 2

Therefore the points (1,2) and (7,2) lie on the given curve.

8 0
3 years ago
The fourth term of a Geometric Progression is 48 and the sixth term is 12. Find the
erastova [34]

Answer:

Common ratio = 1/2 and first term = 384

or common ratio = -1/2 and first term = -384.

Step-by-step explanation:

T6/T4 = r^5 / r^3  where r = the common ratio and T6 and T4 are 6th and 4th terms

r^5 / r^3 = 12/48

r^2 = 1/4

so r = +/- 1/2.

The 4th term = a r^3  where a = first term.

If r = 1/2:-

48 = a *(1/2)^3 = a/8  

a = 8*48

= 384.

if r = -1/2,  then a = -384

7 0
3 years ago
Calculate DE to the hundredths place.
kompoz [17]
<h3>Answer:  9.03</h3>

=====================================================

Explanation:

For now, focus solely on triangle HGF.

We'll need to find the measure of angle F.

Use the law of cosines

f^2 = g^2 + h^2 - 2*g*h*cos(F)

(4.25)^2 = 8^2 + 6^2 - 2*8*6*cos(F)

18.0625 = 100 - 96*cos(F)

18.0625-100 = -96*cos(F)

-81.9375 = -96*cos(F)

cos(F) = (-81.9375)/(-96)

cos(F) = 0.853515625

F = arccos(0.853515625)

F = 31.403868 degrees approximately

---------------------------

Now we can move our attention to triangle DEF.

We'll use the angle F we just found to find the length of the opposite side DE, aka side f.

Once again, we use the law of cosines.

f^2 = d^2 + e^2 - 2*d*e*cos(F)

f^2 = (4.75+8)^2 + (11+6)^2 - 2*(4.75+8)*(11+6)*cos(31.403868)

f^2 = 81.563478

f = sqrt(81.563478)

f = 9.031250 approximately

Rounding to two decimal places means we get the final answer of DE = 9.03

5 0
2 years ago
Johnny's town is having an old-fashioned circus under a large tent. In order to keep the tent from falling down, workers must ti
Zepler [3.9K]

Answer: 62 feet approximately.

Step-by-step explanation:

1. Based on the information given in the problem, you can draw a right triangle as the one shown in the image attached, where the height of the tent is represented with x. Therefore, you can calculate it as following:

sin\alpha=\frac{oppostite}{hypotenuse}

Where:

\alpha=62\°\\opposite=x\\hypotenuse=70

2. Substitute values and solve for x, then the height of the circus tent is:

sin(62\°)=\frac{x}{70}\\x=70*sin(62\°)

x=61.81≈62ft

7 0
3 years ago
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