The length of material needed for the border is the perimeter of the backyard play area
<h3>How to calculate the
length of
material needed </h3>
The area of the play area is given as:
The area of a trapezoid is calculated using:
Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.
The given parameter is not enough to solve the length of material needed.
So, we make use of the following assumed values.
Assume that the parallel sides are: 25 feet and 31 feet long, respectively.
While the other sides are 10.2 feet and 8.2 feet
The length of material needed would be the sum of the above lengths.
So, we have:
Using the assumed values, the length of material needed for the border is 74.4 feet
Read more about perimeters at:
brainly.com/question/17297081
The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.
The conversion between Litres and gallons is about 4L/gal,
so 2L * 1gal/ 4L = 1/2 gal
The 1 gal is about twice as large
Answer:
We can order 35 different types of pizza based on the toppings.
Step-by-step explanation:
There are 3 different types of pizza crust which a person can choose for his pizza. On Monday's company has introduced new campaign in which a person can choose extra toppings of his choice at no additional cost. The topping are of 7 different types. The total number of different pizza which a person can have is 7C3. Solving through computation technique we get 35.
Answer:
with what know question was there
