Let S = {1,2,3,4,5,6,7,8,9,10} be the set of equally likely outcomes for an event. Let event E = {1,2,3,4,5,6} and event F = {2,
4,6,8}.
P(E and F^c) P(E or F) P(E) P(E^c or F^c) P(E^c) P(F) P(F^c)
0.3
0.4
0.6
0.7
P(E and F^c) P(E or F) P(E) P(E^c or F^c) P(E^c) P(F) P(F^c)
0.3
0.4
0.6
0.7
1 answer:
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Answer:
Step-by-step explanation:
First, you should put the axis of symetry as 5, -7 because f(x)= (x-h)^2+k and h is 5 and k is -7. the axis of symetry is x=5 because that is the "folding point" of the graph. Next, you would have to plug In 4 and 6 as your helping points to tell you where the other points of the function are going to be.
Plug 4 in and you get -6. plug 6 in and you get -6. plot the points (4, -6) and (6,-6).
Hope this helps!
:)
