X + y = 2 —> y = 2 - x
insert to first equation
2-x=x^2-3x-6
x^2 - 3x - 6 - 2 + x = 0
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2
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:)
Answer:

Step-by-step explanation:


Answer:
See Explanation
Step-by-step explanation:
The question is not clear. However, I will treat the question as:

and:


Solving:
and 

Divide both sides by 26


Divide both sides by 50

Solving
and 

Express 1 as 2^0

Remove bracket

Cancel out 2

Divide both sides by 6



Express 1 as 5^0

Cancel out 5^0
