Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,
1 answer:
Step-by-step explanation:
Sample space, S = {(1,1),(1,3),(1,4),(1,5),(1,6),(1,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(4,1),(4,3),(4,4),(4,5),(4,6),(4,8)}
These dice will give a sum of 2 with N={(1,1)}, which only has 1 combination
Thus, the probability of rolling a sum of 2 with these dice is
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For this case we have,
- store 1:
3/4 of a bushel of apples -----------------------> $ 9
1 bushel of apples -------------------------------> x
From here the value of x is cleared, resulting in:
- store 2:
2/3 of a bushel of apples -----------------------> $ 9
1 bushel of apples -------------------------------> x
From here the value of x is cleared, resulting in:
Therefore it is convenient to buy apples in store 1 because it is cheaper.
Answer:
It is convenient to buy apples in store 1 because it is cheaper. A division must be made for each case because you want to find the unit cost of a product having the total cost and the amount in fraction.