In B 5^2 = 25. There is no x anywhere.
In C f(x) = 2/x is a function of a reciprocal, not a quadratic.
In D f(x) = 2x^3 + 3x^2 - 5 is a cubic. A cubic is not a quadratic. The highest power of a quadratic is x^2
That leaves A. When you expand the brackets, you get
3(x^2 + 3x- 4x - 12)
2(x^2 - x - 12) when you remove the brackets you get
2x^2 - 2x - 24. The highest power of x is x^2. This is your quadratic.
A<<<< answer.
Note: Since the symbols for greatest integer function (GIF) and least integer function (LIF) are not given, I will be using the words GIF and LIF in the solution
GIF x means largest integer less than or equal to x, and LIF x means least integer greater than or equal to x.
We need to determine which expressions are equal
Option 1: GIF 4.9 and LIF 3.1
GIF 4.9 = 3
LIF 3.1 = 4
Hence GIF 4.9 ≠ LIF 3.1
Option 2: GIF 15.2 and GIF 14.8
GIF 15.2 = 15
GIF 14.8 = 14
Hence, GIF 15.2 ≠ GIF 14.8
Option 3: GIF -6 and LIF -6
GIF -6 = -6
LIF -6 = -6
Hence, GIF -6 = LIF -6
Option 4: LIF -3.2 and LIF -2.6
LIF -3.2 = -2
LIF -2.6 = -1
Hence, LIF -3.2 ≠ LIF -2.6
Hence, only in Option C the pair of expressions are equal.
Answer:
x= (y+40)-(y-330)
Step-by-step explanation:
According to the information provided, the difference in their scores would be the result of subtracting Austin's SAT score from Alexandra's SAT score.
Then, as Alexandra's SAT score was 40 points above the average score this means that you have to add 40 to the average score to get her result. Also, as Austin's SAT score was 330 points below the average score, this means that you have to subtract 330 from the average score. With this you can write the expression:
x= difference in their scores
y= average score
x= (y+40)-(y-330)
Answer:
Mark brainliest please if i am correct one more brainliest please
Step-by-step explanation:
A=a+b
2h=15+25
2·5=100
Answer:
you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines
Step-by-step explanation:
hope this helps:)
