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kolbaska11 [484]
2 years ago
13

Help me pls if you do bless your soul

Mathematics
1 answer:
Umnica [9.8K]2 years ago
6 0

Answer:

x = 73.17

Step-by-step explanation:

To solve this problem we are going to have to use trig function

The three main trig functions are

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Hypotenuse

( where hypotenuse = longest length , opposite = side length opposite of angle and adjacent = other side length )

Here, we are given two side lengths and we want to find an angle.

We are given the hypotenuse and its adjacent ( we know this because we are not given its opposite )

When you have the adjacent and hypotenuse you use cosine.

So we have Cos"x" = adj / hyp

adj = 22 and hyp = 76

So Cos"x" = 22/76

==> take the inverse of cos to both sides

x = 73.17 ( rounded to the nearest hundredth )

and we are done!

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Valerie bought 18yrds of fabric. If she used 9yrds of fabric on her quilt, she will use another 9yrds on her sister's. The total is 18yrds.
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3 years ago
A field has a perimeter of 1.48 kilometers it is 460 meteres long how wide is the field
Vika [28.1K]
280 meters wide. 
Step 1: Convert kilometers to meters. 1.48=1480
Step 2: Multiply the side length that you have by 2. 2x460=920
Step 3: Subtract 920 from 1480. 1480-920=560.
Step 4: Divide 560 by 2. 560/2=280
There is your answer! 
6 0
3 years ago
Read 2 more answers
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
Someone please help me with this one
Anna35 [415]

Answer:

k=-2x+9

Step-by-step explanation:

-4x+6=k*2x-3

+3               +3

-4x+9=k*2x

/2x          /2x

-2x+9=k

8 0
4 years ago
3. What is the solution to the equation 3x = 15? Express the
ivanzaharov [21]

Answer:

x=2.4650

Step-by-step explanation:

I assume that you mean 3^x=15

so let s use the ln() function

ln(3^x)= xln(3)=ln(15)

so x = ln(15)/ln(3)

x = 2.4650

4 0
3 years ago
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