Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
To solve the problem, we need to get the formula for area of a circle -
Area = pi * r^2; r= radius
= 3.14 * (13cm)^2
= 3.14 * 169cm^2 or 3.14 * 13^2cm^2
= 530.66cm^2
Therefore, the area of the circular plate is 530.66cm^2
Answer:
equals what ie tablespoons lbs ??
Step-by-step explanation:
