Question

A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?

Answer 1

The slope of first line is m 1= ( 1 - 0 ) / ( - 2 - ( - 6 ) );
m = 1 / 4 ;
Because the second line is perpendicular to the first line, m2 * m1 = - 1 ;
m2 * ( 1 / 4 ) = -1;
 m2 = - 4 ;
The equation of the second line is : y - 3 = ( - 4 )( x - 2 );
y - 3 = -4x + 8 ;
y = -4x + 11.