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Contact [7]
4 years ago
12

If 2x/3−x/10=17/10, then x = ?

Mathematics
1 answer:
DedPeter [7]4 years ago
8 0

Answer:

x=3

Step-by-step explanation:

2x/3−x/10=17/10

Multiply each side by 30 to get rid of the fractions

30( 2x/3−x/10)=(17/10)*30

Distribute

20x -3x = 51

Combine like terms

17x = 51

Divide by 17

17x/17 = 51/17

x=3

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I need help with this too
DiKsa [7]

Answer:

Angle HFG + angle ACB = 90°

Angle EFC = Angle DFG

Angle HFG + angle DFH = angle DFG

= 90°

The answer is B Angle DFH = angle ACB

Hope this helps!

7 0
4 years ago
Help? Please? Mathematics isn't my thing.
Natali5045456 [20]
C is the correct answer. The equation for f(x) is f(x)=1.8x-10 and the equation for g(x) is g(x)=-4 . Since we're trying to find the input value for x where f(x)=g(x) make the 2 equations equal to each other and you'll get your answer.
4 0
4 years ago
Help me on this please
Solnce55 [7]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Store sold 72 books if ratio of books to bookmarks was 9:2, How many bookmarks did the store sell?
vaieri [72.5K]
If the store sold 9 books for every 2 bookmarks they sold 9 books 8 times selling 72 books in total so now you have to multiply 8*2 to get how many bookmarks were sold that day.

7 0
3 years ago
Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =
lara [203]

The domain and range of a function are the possible <em>x and y values </em>of the function.

<em>The domain and the range of the function is: (a) </em>\mathbf{D:\{x \in R|x \ne -2,2\}}<em> and </em>\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}<em />

The functions are given as:

\mathbf{f(x) = \frac{4}{x^2 - 4}}

\mathbf{g(x) = x + 2}

(g o f)(x) is calculated as:

\mathbf{(g\ o\ f)(x) = g(f(x))}

So, we have:

\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}

Take LCM

\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }

\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }

Represent the denominator as follows, to calculate the domain

\mathbf{x^2 - 4 \ne 0 }

Add 4 to both sides

\mathbf{x^2 \ne 4 }

Take square roots of bot sides

\mathbf{x \ne \±2 }

Hence, the domain of the function is:

\mathbf{D:\{x \in R|x \ne -2,2\}}

On the graph of \mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} } (see attachment), the function does not have a value from <em>y = 1 to 2.</em>

Hence, the range is:

\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}

Read more about domain and range at:

brainly.com/question/1632425

5 0
2 years ago
Read 2 more answers
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