1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Certain fast growing bacteria can reproduce in 12 minutes. If you begin with 100 bacteria, how many bacteria will there be 36 mi
1 answer:
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Answer:
Javier's parents set aside $1500 when he was born
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:
In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this question, we have that:
We have to find P. So
Javier's parents set aside $1500 when he was born