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Anastasy [175]
3 years ago
9

Pls help! Use the quadratic formula to solve the equation -x^2+7=5

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

x = -√2, x2 = √2

Alternative Form:

x1 = -1.41421, x2 = 1.41421

Step-by-step explanation:

-x²+7-5 = 0

-x²+2 = 0

x = -0±√0²-4×(-1)×2 [over] 2×(-1)

x = ±√0+8 [over] -2

x = ±√8 [over] -2

x = ±2√2 [over] -2

x = -±2√2 [over] 2

x = -2√2 [over] 2

x = --2√2 [over] 2

x = -√2

x = √2

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Triangle DEF is congruent to right triangle GHI with a right angle at vertex H. If the slope of DE is –2, what must be true?
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<em><u>Question:</u></em>

Triangle DEF is congruent to right triangle GHI with a right angle at vertex H. If the slope of DE is –2, what must be true?

A. The slope of HI is 1/2.

B. The slope of EF is 1/2.

C. The slope of GH is –2.

C. The slope of DF is –2.

<em><u>Answer:</u></em>

The slope of HI is 1/2

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<em><u>Solution:</u></em>

Given that,

Triangle DEF is congruent to right triangle GHI

Which means,

These pairs of angles are congruent

{D, G}, {E, H}, and {F, I}

In triangle DEF, E is a right angle

This means that the line segments  \overline{DE}\ and\ \overline{EF} are perpendicular.

We know that,

Product of slope of a line and slope of line perpendicular to that line is equal to -1

Given that,

Slope of DE = -2

\text{ Slope of DE } \times \text{ slope of EF} = -1\\\\-2 \times \text{ slope of EF} = -1\\\\\text{ slope of EF} = \frac{1}{2}

Since the sides EF and HI are congruent,

Slopes of parallel lines are equal

Slope\ of\ HI\ = \frac{1}{2}

Thus, Slope of HI is 1/2

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