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ra1l [238]
2 years ago
15

What is the least whole number n such that 84 divides n! ?

Mathematics
1 answer:
777dan777 [17]2 years ago
6 0

Answer:

5 should be the correct answer

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Less than 75% of workers got their job through internet resume sites. A researcher thinks it has increased.
Vera_Pavlovna [14]

Answer:

H0 : p = 0.75  against    H1: p > 0.75  One tailed test.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0 : p = 0.75  against    H1: p > 0.75  One tailed test.

In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.

The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.

As H0 is supposed to be less than we choose H1 to be greater than equality.

5 0
3 years ago
A professional volleyball
andre [41]

Answer: Lost 44%, Games won: 28/50

Step-by-step explanation:

Percentage = (part / whole) * 100

The total number of games the team played is 28 + 22, which equals 50.

Percentage of losses = (22/50) * 100 = 44%

Fraction of wins = 28/50

3 0
3 years ago
what is the original price and the markup to find the retail price. Original price: $44; Markup: 7.5%
torisob [31]

Answer:

the retail price is $47.30

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP!! I know I need to factor but I’m confused…
Veseljchak [2.6K]

Answer:

x = 16

Step-by-step explanation:

Given a tangent and a secant from an external point to a circle, then

The product of the external part and the whole of the secant is equal to the square of the tangent, that is

9(9 + x) = 15²

9(9 + x) = 225 ( divide both sides by 9 )

9 + x = 25 ( subtract 9 from both sides )

x = 16

5 0
3 years ago
Read 2 more answers
How you will find out the value of 'n ' ?
saw5 [17]

Answer:

I don't know

Step-by-step explanation:

How you will find out the value of 'n ' ?

[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]

8 0
3 years ago
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