Answer:
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.
The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.
As H0 is supposed to be less than we choose H1 to be greater than equality.
Answer: Lost 44%, Games won: 28/50
Step-by-step explanation:
Percentage = (part / whole) * 100
The total number of games the team played is 28 + 22, which equals 50.
Percentage of losses = (22/50) * 100 = 44%
Fraction of wins = 28/50
Answer:
the retail price is $47.30
Step-by-step explanation:
Answer:
x = 16
Step-by-step explanation:
Given a tangent and a secant from an external point to a circle, then
The product of the external part and the whole of the secant is equal to the square of the tangent, that is
9(9 + x) = 15²
9(9 + x) = 225 ( divide both sides by 9 )
9 + x = 25 ( subtract 9 from both sides )
x = 16
Answer:
I don't know
Step-by-step explanation:
How you will find out the value of 'n ' ?
[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]