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cestrela7 [59]
3 years ago
6

Reduce 720/1080 little cunfused

Mathematics
2 answers:
Veronika [31]3 years ago
8 0
To reduce a fraction, divide the numerator and the denominator equally until they reach the simplest whole number possible. 

In this case, the numerator (720) and the denominator (1080) can both be divided by 360 to get 2/3, our reduced fraction. 

Irina18 [472]3 years ago
7 0
\frac{720}{1080}

\frac{360}{540}

\frac{180}{270}

\frac{90}{135}

\frac{30}{45}

\frac{10}{15}

\frac{2}{3}


answer

\frac{2}{3}



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determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution. x+y=5 2x-y=-
max2010maxim [7]

Answer:

(2/3, 13/3)    (Exactly one solution)

Step-by-step explanation:

Write these equations in a column:

 x+y=5

2x-y=-3

Note that we can eliminate y immediately by adding these two equations together. We get:

3x = 2, so that x = 2/3.

Substituting 2/3 for x in the first equation, we get:

2/3 + y = 5.  Clear out fractions by multiplying all three terms by 3:

2 + 3y = 15, or 3y = 13.  Then y = 13/3, and the solution is

(2/3, 13/3)      There is exactly one solution.

7 0
4 years ago
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4. Three hoses are connected end to end. The first hose is
Yuri [45]

Answer:7.25 feet

Step-by-step explanation:

6.25+6.5=12.75

20-12.75=7.25

4 0
3 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
Create an expression whose value will be 21 when x = -6
Svetach [21]
21=27+x 

If you replace x with -6 then your answer will be 21!! 
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4 years ago
Line parallel to y=1/2x-5
Sveta_85 [38]

Answer:

1/2

Step-by-step explanation:

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