Answer:
Step-by-step explanation:
Are u stupid?
Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
You're on the right track. Start by combining like terms on the left side of the equation by adding 56 and 34.
90 = n + 30, now subtract 30 from both sides of the equation to isolate the variable n.
60 = n is the answer.
X is 5 in this case!!!!hope it helps
Triangle ABE is isosceles / Given
AB congruent to AE / Def isosceles
angle ABE congruent to angle AEB / Property of isosceles triangles
angle ABD congruent to angle AEC / Subst different name for same angles
BD congruent to EC / Given
triange ABD congruent to triange AEC / Side Angle Side
