The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
Step-by-step explanation:
The coordinates of point A (2,8) and C (5,2)
The measure of segment AC
If you slowly increase the strength of an electric current flowing through the wire, you would expect the magnet to become stronger. The correct option among all the options that are given in the question is the first option or option "a". The magnetic field around the wire becomes stronger. I hope it helps you.
Answer:
hcf:3x^3-6x^2+y^2-3x+54
lcm:2(x+3)(x^2-3x+9)(x^3-3x^2+9)(y^2-3x+9)
basically you treat y like a number and not a variable
Answer:
a is 4
b is 2y
c is -10y²+9
discriminant is 4(41y²-36)
Step-by-step explanation:
4x²+2xy-10y²+9=0
rewrite in standard form of a quadratic equation like ax² + bx + c = 0
4x²+2yx-10y²+9=0
basically you treat y like a number and not a variable
a is the number with the x²
right away we know a is 4 because of 4x²
b is the one with x so in this formula b is 2y
c is the number without the x which in this case is -10y²+9
discriminant is
b² - 4ac
(2y)²- (4)(4)(-10y²+9)
4y²-(16)(-10y²+9)
4y²-(16)(-10y²+9)
4y²+160y²-144
164y²-144 =
4(41y²-36)
