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vagabundo [1.1K]
3 years ago
12

Anyone know the answer to this?

Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0
<h3>Answer: Choice D which is (13-5x)/(2x-8)</h3>

======================================

Explanation:

Fractions in all honesty are quite simply a pain. They complicate things greatly. Luckily we can cancel out some of the fractions here. Note we have inner fractions 3/(x-2) and 4/(x-2), both of which having a denominator of (x-2).

Focus on just the stuff up top which is 3/(x-2) - 5. Multiply both of the terms by the expression (x-2) to get the fraction 3/(x-2) turning into just 3. The 5 becomes 5(x-2) = 5x-10. So we end up with the expression 3 - (5x-10) = 3-5x+10 = 13-15x up top

Similarly, in the denominator we have 2 - (4/(x-2)) which becomes 2(x-2) - 4 = 2x-4-4 = 2x-8 when we multiply everything by (x-2) to cancel out that inner fraction.

So that's how we end up with (13-5x) all over (2x-8) as our final answer.

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What is the solution set to the inequality –3x + 5.9 ≥ –15.4 for x in the set {–10, –5, 0, 5, 10}?
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8 0
3 years ago
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What is 6/54 equivalent to
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3 years ago
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Please help I will brainliest!! Really urgent!!
asambeis [7]

Answer:1/9(x+0.1)

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8 0
3 years ago
128 POINTS IF YOU HELP
Aleksandr-060686 [28]
(A) We let y = the cost and are told x = the number of people. Since you pay $20 per person, the cost is 20x. That is, y=20x

(B) Again, let the cost =y and the number of people is given as x. You pay $10 per person or 10x plus an additional $50 for the room. That is, y=10x+50

(c) Link to graphs: https://www.desmos.com/calculator but if that doesn't work see the attachment for a screen shot. You just have to put the equations (type them) at left and the graph comes automatically.

(D) The admission price is the same when the two equations are equal. You can find this by setting them equal to each other as such: 20x = 10x+50 and solving for x. However, since you just graphed them the point of intersection (where the lines share/have the same point) gives the information. Remembers that (x,y) = (people, cost). The graphs intersect at (5, 100) so for 5 people the cost is the same and the cost is $100.

(E) For the regular rate we let x = 6 and solve for y (the cost). We get y = 20x which is y = (20)(6)=120. It costs $120 using the regular rate to take 6 people. Now let's use the equation for the group rate again with x = 6. Here we get y = 10x +50 or y = 10(6)+50 = $110. The group rate costs $110.

(F) The cost is the same at 5 people but if there are more than five the group rate is better as we saw in part E. So the regular rate is better for less than 5 people.

(G) Here y = $150. Let us use the group rate formula and solve for x (the number of people). 10x+50 = 150 so 10x = 100 and x = 10. Since 10 is more than 5 this is the better deal. However if you don't believe it or want to double check we can solve for x using y = 150 and the regular rate equation. We get: 20x = 150 so x = 7.5 Since we can't bring half a person we would only be able to bring 7 and that is less than 10 so this is not the best choice. Use the group rate and bring 10 people!

8 0
3 years ago
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