Answer is C have a nice day
Answer:
Step-by-step explanation:
To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.
a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:
we can substitute the value of sec(θ) in this equation:
and solve for for cos(θ)
side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by 
b) since right triangle is mentioned in the question. We can use:
we know the value of cos(θ)=1\52. and by comparing the two. we can say that:
- length of the adjacent side = 1
- length of the hypotenuse = 52
we can find the third side using the Pythagoras theorem.
- length of the opposite side = √(2703) ≈ 51.9904
we can find the sin(θ) using this side:
and since 
Answer:
a = 24*1/3
a =8
Step-by-step explanation:
We are using proportions to solve this problem by putting students over adults
students 3 24
--------------- = --------------- = -------------
adults 1 a
where a is the unknown number of adults
Using cross products
3a=24*1
Divide by 3
a = 24*1/3
a = 24/3
a = 8
This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
