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Tanya [424]
3 years ago
10

The cake store is having a

Mathematics
1 answer:
professor190 [17]3 years ago
4 0

Answer:

I believe the answer is $2.25

Step-by-step explanation:

To figure this out, first you need to find 25% as a decimal. 25% as a decimal is .25 . Then, you multiply 9 by .25 . 9 * .25 = $2.25. You are saving $2.25 with the discount.

Hope this helps :)


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Find the area of the shape shown below pls
Afina-wow [57]

Step-by-step explanation:

area of missed triangle =1/2×2×4=4 cm2

area of whole rectangle =4×8=32 cm2

area of shape =32_4 =28cm2

6 0
2 years ago
Solve for v.<br>2y = 18-41<br>Simplify your answer as much as possible.<br>​
Sloan [31]

Answer:

y = -11.5

Step-by-step explanation:

2y = 18-41

Combine like terms

2y = -23

Divide each side by 2

2y/2 = -23/2

y = -11.5

7 0
3 years ago
Quiz
andreyandreev [35.5K]
I don’t see a pic for this
8 0
3 years ago
Sally is standing at one corner of a snowy rectangular field that measures 200 ft by 200 ft. She wishes toreach a warm cabin loc
pshichka [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin.

Step-by-step explanation:

From the question we are told that

   The speed from the point Sally is standing to the point P is  u =  3 \  ft /s

   The speed from the point P to the cabin is v  =  5 \  ft /s

   

Let denote the distance from the bottom left corner to the  P  be  y  ft

 Generally according to Pythagoras theorem the distance from Sally's first position to point P is mathematically represented as

          s = \sqrt{y^2 + 200^2}

Generally the distance from that point P to the cabin is mathematically represented as

       d =  200 -y

Generally the time it takes Sally to cover that distance s is mathematically represented as

       t_1 =  \frac{s}{u}

=>     t_1 =  \frac{ \sqrt{y^2 + 200^2}}{3}

Generally the time it takes Sally to cover that distance d is mathematically represented as

       t_2 =  \frac{d}{v}

=>     t_2 =  \frac{ 200 - y }{5}

So the total time taken is  

        t= \frac{ \sqrt{y^2 + 200^2}}{3}  +  \frac{ 200 - y }{5}

Generally the minimum time taken with respect to the distance is mathematically evaluated by differentiating and equating the derivative to 0

So  

     \frac{dt}{dy} =\frac{1}{3} \frac{y}{ \sqrt{y^2 + 200^2} }  -  \frac{1}{5}  =0      

=> \frac{dt}{dy} = \frac{y^2 }{y^2 + 200 ^2} =\frac{9}{25}

=> 25y^2 = 9y^2 + 9 * 200^2        

=> 16y^2 = 360000          

=> y = 150

So the distance from point P to the cabin is  

           d =  200 -150

=>       d =  50 \ ft

So  the optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin

       

8 0
2 years ago
How would you use estimation to evaluate this expression: 10.2 × [(2×3.7)+8]
tresset_1 [31]
Well, first you would estimate all the terms: 10.2 to 10, 2 to 2(keep the same), 3.7 to 4, and eight to eight.

So you have 10 x [(2 x 4) + 8]
then you would evaluate this expression using order of operations
 
10 x [(2 x 4) + 8]
10 x [8 +  8] 
10 x 16
160
4 0
3 years ago
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