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3 years ago

The cake store is having a

Mathematics

1 answer:

professor190 [17]3 years ago

4 0

Answer:

I believe the answer is $2.25

Step-by-step explanation:

To figure this out, first you need to find 25% as a decimal. 25% as a decimal is .25 . Then, you multiply 9 by .25 . 9 * .25 = $2.25. You are saving $2.25 with the discount.

Hope this helps :)

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Find the area of the shape shown below pls

Afina-wow [57]

Step-by-step explanation:

area of missed triangle =1/2×2×4=4 cm2

area of whole rectangle =4×8=32 cm2

area of shape =32_4 =28cm2

6 0

2 years ago

Solve for v.<br>2y = 18-41<br>Simplify your answer as much as possible.<br>

Sloan [31]

Answer:

y = -11.5

Step-by-step explanation:

2y = 18-41

Combine like terms

2y = -23

Divide each side by 2

2y/2 = -23/2

y = -11.5

7 0

3 years ago

Quiz

andreyandreev [35.5K]

I don’t see a pic for this

8 0

3 years ago

Sally is standing at one corner of a snowy rectangular field that measures 200 ft by 200 ft. She wishes toreach a warm cabin loc

pshichka [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The optimal point(i.e the position of P) that will allow Sally to reach the cabin as quickly as possible is $d = 50 \ ft$ from the cabin.

Step-by-step explanation:

From the question we are told that

The speed from the point Sally is standing to the point P is $u = 3 \ ft /s$

The speed from the point P to the cabin is $v = 5 \ ft /s$

Let denote the distance from the bottom left corner to the P be y ft

Generally according to Pythagoras theorem the distance from Sally's first position to point P is mathematically represented as

$s = \sqrt{y^2 + 200^2}$

Generally the distance from that point P to the cabin is mathematically represented as

$d = 200 -y$

Generally the time it takes Sally to cover that distance s is mathematically represented as

$t_1 = \frac{s}{u}$

=> $t_1 = \frac{ \sqrt{y^2 + 200^2}}{3}$

Generally the time it takes Sally to cover that distance d is mathematically represented as

$t_2 = \frac{d}{v}$

=> $t_2 = \frac{ 200 - y }{5}$

So the total time taken is

$t= \frac{ \sqrt{y^2 + 200^2}}{3} + \frac{ 200 - y }{5}$

Generally the minimum time taken with respect to the distance is mathematically evaluated by differentiating and equating the derivative to 0

$\frac{dt}{dy} =\frac{1}{3} \frac{y}{ \sqrt{y^2 + 200^2} } - \frac{1}{5} =0$

=> $\frac{dt}{dy} = \frac{y^2 }{y^2 + 200 ^2} =\frac{9}{25}$

=> $25y^2 = 9y^2 + 9 * 200^2$

=> $16y^2 = 360000$

=> $y = 150$

So the distance from point P to the cabin is

$d = 200 -150$

=> $d = 50 \ ft$

So the optimal point(i.e the position of P) that will allow Sally to reach the cabin as quickly as possible is $d = 50 \ ft$ from the cabin

8 0

2 years ago

How would you use estimation to evaluate this expression: 10.2 × [(2×3.7)+8]

tresset_1 [31]

Well, first you would estimate all the terms: 10.2 to 10, 2 to 2(keep the same), 3.7 to 4, and eight to eight.

So you have 10 x [(2 x 4) + 8]
then you would evaluate this expression using order of operations

10 x [(2 x 4) + 8]
10 x [8 + 8]
10 x 16
160

4 0

3 years ago